From 0381122ad58d8bc792925c3db49f829ae925d371 Mon Sep 17 00:00:00 2001
From: Andrew Kesterson <andrew@aklabs.net>
Date: Thu, 4 Jun 2026 13:26:21 -0400
Subject: [PATCH] WIP

---
 05-photoresistors/README.md | 3 ---
 1 file changed, 3 deletions(-)

diff --git a/05-photoresistors/README.md b/05-photoresistors/README.md
index 1fb8657..219984a 100644
--- a/05-photoresistors/README.md
+++ b/05-photoresistors/README.md
@@ -15,9 +15,6 @@ So when I looked at the circuit diagram, I wondered, "why are we measuring the v
 The answer is because, as it turns out, if you take the measurement downstream of the photoresistor in this particular example, you will always read 0v. You will never see a change in the output voltage from the photoresistor. In order to see the impact of the photoresistor in the circuit, you need to measure upstream of the photoresistor.
 
 <center><img alt="wot" width="320" src="wot.jpeg"/></center>
-<br/>
-<center><i>The face of a man who realizes he has failed to grasp something fundamental</i></center>
-<br/>
 
 If you remember back to [tutorial 4 with Analog Digital Conversion](../04-adc/README.md#measuring-potentiometers), I talked about potentiometers, and how they are a `voltage divider`.