diff --git a/05-photoresistors/README.md b/05-photoresistors/README.md
index d3a6e70..1fb8657 100644
--- a/05-photoresistors/README.md
+++ b/05-photoresistors/README.md
@@ -14,13 +14,10 @@ So when I looked at the circuit diagram, I wondered, "why are we measuring the v
 
 The answer is because, as it turns out, if you take the measurement downstream of the photoresistor in this particular example, you will always read 0v. You will never see a change in the output voltage from the photoresistor. In order to see the impact of the photoresistor in the circuit, you need to measure upstream of the photoresistor.
 
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+<center><img alt="wot" width="320" src="wot.jpeg"/></center>
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-<i>The face of a man who realizes he has failed to grasp something fundamental</i>
+<center><i>The face of a man who realizes he has failed to grasp something fundamental</i></center>
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 If you remember back to [tutorial 4 with Analog Digital Conversion](../04-adc/README.md#measuring-potentiometers), I talked about potentiometers, and how they are a `voltage divider`.