From 7031a3c393148900ce85f43361fb3c3df4075bc3 Mon Sep 17 00:00:00 2001 From: Andrew Kesterson Date: Thu, 4 Jun 2026 13:25:36 -0400 Subject: [PATCH] WIP --- 05-photoresistors/README.md | 7 ++----- 1 file changed, 2 insertions(+), 5 deletions(-) diff --git a/05-photoresistors/README.md b/05-photoresistors/README.md index d3a6e70..1fb8657 100644 --- a/05-photoresistors/README.md +++ b/05-photoresistors/README.md @@ -14,13 +14,10 @@ So when I looked at the circuit diagram, I wondered, "why are we measuring the v The answer is because, as it turns out, if you take the measurement downstream of the photoresistor in this particular example, you will always read 0v. You will never see a change in the output voltage from the photoresistor. In order to see the impact of the photoresistor in the circuit, you need to measure upstream of the photoresistor. -
-wot - +
wot

-The face of a man who realizes he has failed to grasp something fundamental +
The face of a man who realizes he has failed to grasp something fundamental

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If you remember back to [tutorial 4 with Analog Digital Conversion](../04-adc/README.md#measuring-potentiometers), I talked about potentiometers, and how they are a `voltage divider`.