diff --git a/05-photoresistors/README.md b/05-photoresistors/README.md
index e1bf596..7b0bd90 100644
--- a/05-photoresistors/README.md
+++ b/05-photoresistors/README.md
@@ -14,8 +14,13 @@ So when I looked at the circuit diagram, I wondered, "why are we measuring the v
 
 The answer is because, as it turns out, if you take the measurement downstream of the photoresistor in this particular example, you will always read 0v. You will never see a change in the output voltage from the photoresistor. In order to see the impact of the photoresistor in the circuit, you need to measure upstream of the photoresistor.
 
-<center><img alt="wot" src="wot.jpeg"/></center>
-<center><i>The face of a man who realizes he has failed<br/>to grasp something very fundamental</i></center>
+<center>
+<img alt="wot" src="wot.jpeg"/>
+<br/>
+*The face of a man who realizes he has failed*
+
+*to grasp something very fundamental*
+</center>
 
 If you remember back to [tutorial 4 with Analog Digital Conversion](../04-adc/README.md#measuring-potentiometers), I talked about potentiometers, and how they are a `voltage divider`.