From 8eab70d5be7aed91d5e8846ec05d33cf75caf994 Mon Sep 17 00:00:00 2001 From: Andrew Kesterson Date: Thu, 4 Jun 2026 13:23:49 -0400 Subject: [PATCH] WIP --- 05-photoresistors/README.md | 9 +++++++-- 1 file changed, 7 insertions(+), 2 deletions(-) diff --git a/05-photoresistors/README.md b/05-photoresistors/README.md index e1bf596..7b0bd90 100644 --- a/05-photoresistors/README.md +++ b/05-photoresistors/README.md @@ -14,8 +14,13 @@ So when I looked at the circuit diagram, I wondered, "why are we measuring the v The answer is because, as it turns out, if you take the measurement downstream of the photoresistor in this particular example, you will always read 0v. You will never see a change in the output voltage from the photoresistor. In order to see the impact of the photoresistor in the circuit, you need to measure upstream of the photoresistor. -
wot
-
The face of a man who realizes he has failed
to grasp something very fundamental
+
+wot +
+*The face of a man who realizes he has failed* + +*to grasp something very fundamental* +
If you remember back to [tutorial 4 with Analog Digital Conversion](../04-adc/README.md#measuring-potentiometers), I talked about potentiometers, and how they are a `voltage divider`.