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Andrew Kesterson
2026-06-04 13:24:51 -04:00
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05-photoresistors/README.md
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@@ -15,11 +15,11 @@ So when I looked at the circuit diagram, I wondered, "why are we measuring the v
The answer is because, as it turns out, if you take the measurement downstream of the photoresistor in this particular example, you will always read 0v. You will never see a change in the output voltage from the photoresistor. In order to see the impact of the photoresistor in the circuit, you need to measure upstream of the photoresistor. The answer is because, as it turns out, if you take the measurement downstream of the photoresistor in this particular example, you will always read 0v. You will never see a change in the output voltage from the photoresistor. In order to see the impact of the photoresistor in the circuit, you need to measure upstream of the photoresistor.
<center> <center>
<img alt="wot" src="wot.jpeg"/> <img alt="wot" width="320" src="wot.jpeg"/>
<br/>
*The face of a man who realizes he has failed*
*to grasp something very fundamental* <br/>
<i>The face of a man who realizes he has failed<br/>
to grasp something very fundamental</i>
</center> </center>
If you remember back to [tutorial 4 with Analog Digital Conversion](../04-adc/README.md#measuring-potentiometers), I talked about potentiometers, and how they are a `voltage divider`. If you remember back to [tutorial 4 with Analog Digital Conversion](../04-adc/README.md#measuring-potentiometers), I talked about potentiometers, and how they are a `voltage divider`.