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Andrew Kesterson
2026-06-04 13:24:51 -04:00
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05-photoresistors/README.md
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@@ -15,11 +15,11 @@ So when I looked at the circuit diagram, I wondered, "why are we measuring the v
The answer is because, as it turns out, if you take the measurement downstream of the photoresistor in this particular example, you will always read 0v. You will never see a change in the output voltage from the photoresistor. In order to see the impact of the photoresistor in the circuit, you need to measure upstream of the photoresistor.
<center>
<img alt="wot" src="wot.jpeg"/>
<br/>
*The face of a man who realizes he has failed*
<img alt="wot" width="320" src="wot.jpeg"/>
*to grasp something very fundamental*
<br/>
<i>The face of a man who realizes he has failed<br/>
to grasp something very fundamental</i>
</center>
If you remember back to [tutorial 4 with Analog Digital Conversion](../04-adc/README.md#measuring-potentiometers), I talked about potentiometers, and how they are a `voltage divider`.